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3.4x^2+4.5x-9.4=0
a = 3.4; b = 4.5; c = -9.4;
Δ = b2-4ac
Δ = 4.52-4·3.4·(-9.4)
Δ = 148.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{148.09}}{2*3.4}=\frac{-4.5-\sqrt{148.09}}{6.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{148.09}}{2*3.4}=\frac{-4.5+\sqrt{148.09}}{6.8} $
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